Question

2. A player catches a ball of mass 150 gm moving at a rate of 20 m/s. If the process of catching is to be completed in 0.1 sec. What is the force exerted by the ball on the hands of the player?

Answer 1

Answer:-

M=150g

v=20m/s

t=0.1s

a=(v−u)/t

=(20)/0.1

=200m

f=ma

=150×200

=30000/1000

=30N

Hope it helps