Question

2. A point P is 17 cm away from the centre of the circle and the length of tangent drawn from
P to the circle is 15 cm. Find the radius of the circle.​

Answer 1

Answer:

8 cm

Step-by-step explanation:

since we have a tangent of 15 cm and drawing a perpendicular from the centre to the tangent we form a right angle triangle

now, hypotenuse = 17cm,  base = 15 cm and height = radius of the circle = x cm

so using Pythagoras theorem we get

$hypotenuse^{2} = base^{2} + height^{2} \\=> x^{2} = 17^{2} - 15^{2}\\=> x = \sqrt{289 - 225}\\=> x = \sqrt{64}\\=> x= 8 cm$

Answer 2

Answer:

hypotenuse = 17cm, base = 15 cm and height = radius of the circle = x cm

so using Pythagoras theorem we get

\begin{gathered}hypotenuse^{2} = base^{2} + height^{2} \\= > x^{2} = 17^{2} - 15^{2}\\= > x = \sqrt{289 - 225}\\= > x = \sqrt{64}\\= > x= 8 cm\end{gathered}

hypotenuse

2

=base

2

+height

2

=>x

2

=17

2

−15

2

=>x=

289−225

=>x=

64

=>x=8cm

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