Question

2. A police car accelerates quickly to 60m/s in pursuit of a minivan recklessly speeding along the highway at a speed of 45m/s. How long will it take the police car to catch-up with the minivan if it was 600m ahead from the police car at the beginning of the chase?(Show thestep-wise working) (a)40s (b)10s (c)15s (d)none of the above

Answer 1

Answer:

Explanation:

1. You have that:

 -The police car accelerates 60 meters per second.

 - The minivan has a speed of 45 meters per second and is 600 meters ahead of the police car at the beginning of the chase.

 2. Therefore, you have:

 V1xt=V2xt-600

 V1 is the speed of the minivan and V2 is the speed of the police car

 3. The time is:

 t=-600/V1-V2

 t=-600/(45-60)

 t=40 seconds

Answer 2

Given,

speed of police car  $V_p = 60 \frac{m}{s}$

speed of minivan $V_m = 45 \frac{m}{s}$

distance between police car and minivan $S = 600m$

Now, time taken by police to reach the minivan is

$time=\frac{distance\_ between\_ vehicles}{relative\_ speed\_of\_vehicles}$

relative speed of vehicles = $V_p-V_m$

then,

$t = \frac{600}{V_p-V_m}\\ \\t = \frac{600}{60-(+45)}$

since the both vehicles travelling in same direction the sign of speeds will be positive for both vehicles.

Therefore,

$t= \frac{600}{60-45}\\\\ t= \frac{600}{15}\\\\ t=40 sec$

∴Time take by the police car to catch-up with the minivan is $t = 40sec$

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