Question

2. A positive number is 5 times another number. If 21 is added to both the numbers, 2
then one of the new numbers becomes twice the other new number. What are the
numbers?
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Answer 1

Answer:

this shall be the correct answer

Step-by-step explanation:

x=5y

21+x=5y+21

21+x=2(5y+21)

=21+x=2(x+21)

=21+x=2x+42

=x-2x=42-21

-x=21

x=-21

y=5×21

=105

Answer 2

Answer:

Numbers are 7 and 35

Step-by-step explanation:

let first number be x

then second number is 5x

If 21 is added to both the numbers

by solving this equation, we get

$(5x+21)=2(x+21)\\5x+21=2x+42\\\\5x-2x=42-213x=21\\x=\frac{21}{3} \\x=7$

first number is 7

Second number is 5 x 7= 35

Numbers are 7 and 35