Question

2. A positive number is 5 times another number .if 21 is added to both the numbers, then one of the new
numbers becomes twice the other new number. What are the numbers?
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Answer 1

Answer:

let the other number be X

then the number be 5x

new number = X+21

new number 5x+21

here saying twice the other number

a/q

2(X+21)=5x+21

= 2x+42 =5x+21

=2x-5x=21-42

=. –3x =–21

=. minus cancel

=3x =21

X= 21/3

X=07....

if it is helpful please follow..........

Step-by-step explanation:

hence answer is 07...

other number = 7

twice number be 5x = 5×7 =35 ......

Answer 2

Answer:

7

Step-by-step explanation:

let the no. be x

Then the 1st no. is 5x+21

and 2nd no. is 2(x+21)

A/Q

=5x+21=2(x=21)

=5x+21=2x+42

=5x-2x=42-21

=3x=21

=x=21/3

=x=7