Question

2. A positive number is 5 times another number. If 21 is added to both the numbers, then one of the new
numbers becomes twice the other new number. What are the numbers?
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Answer 1

Answer:

1 st no. = x = 7

2 nd no. = 5x = 7X 5 = 35

Step-by-step explanation:

1 st no. = x

2 nd no. = 5 times x so 5x

ATQ,

                              2(x+21)=5x+21

                               2x+42=5x+21                                                                                                                                          

                               2x-5x=21-42                                          

                                     3x=21

                                      x=21/3=7

                                  1 st no. = x = 7

                         2 nd no. = 5x = 7X 5 = 35

                                       

Answer 2

Answer:

The numbers are:

• First number = 35
• Second number = 7

Step-by-step explanation:

Let us assume:

• First number be x.
• Second number be y.

Here, x > y

Given that:

• A positive number is 5 times another number.

→ x = 5y _____(i)

• 21 is added to both the numbers, then one of the new numbers becomes twice the other new number.

→ x + 21 = 2(y + 21) _____(ii)

To Find:

• What are the numbers?

Finding the numbers:

In equation (ii),

→ x + 21 = 2(y + 21)

• Substituting the value of x.

→ 5y + 21 = 2(y + 21)

→ 5y + 21 = 2y + 42

→ 5y - 2y = 42 - 21

→ 3y = 21

→ 3 × y = 3 × 7

• Both sides 3 cancelled.

→ y = 7

Now, In equation (i),

→ x = 5y

→ x = 5 × 7

→ x = 35

The numbers are:

• First number = x = 35
• Second number = y = 7