Question

2. A projectile is thrown at an angle of 30° with
a velocity of 10m/s. the change in velocity
during the time interval in which it reaches
the highest point is
1) 10 m/s
2) 5 m/s
3) 5 13 m/s 4) 10/3 m/s​

Answer 1

Answer:

So the Ans is C-->5.

Explanation:

This because at the highest point the vertical component becomes zero and only horizontal component remains i.e. 10cos30.Thus change is initial minus final , which  gives us 10sin30=10*0.5=5.