Question

2)A pump raises water by spending 5x10^5 j of energy in 10 seconds. Find the power of the pump​

Answer 1

Given :

A pump raises water by spending 5×10⁵ J of energy in 10 seconds.

To Find :

Power of the pump.

Solution :

❖ Power is defined as the rate of work done per unit time.

Mathematically, Power = Work / Time

• It is a scalar quantity having only magnitude.
• SI unit : W (watt)
• Dimension formula : [M¹L²T‾³]

♦ We know that work done is always equal to the change in energy.

∴ Work done = 5 × 10⁵ J

By substituting the given values;

$\sf:\implies\:Power=\dfrac{Work}{Time}$

$\sf:\implies\:Power=\dfrac{5\times10^5}{10}$

$\sf:\implies\: Power=5\times10^4$

$:\implies\:\underline{\boxed{\bf{\purple{Power=50\:kW}}}}$

Knowledge BoosteR :

$\sf\circledast\:1\:J=10^7\:erg$

$\sf\circledast\:1\:eV=1.6\times10^{-19}\:J$

$\sf\circledast\:1\:MeV=10^6\:eV$

$\sf\circledast\:1\:amu=931\:MeV$

$\sf\circledast\:1\:kilowatt=10^3\:W$

$\sf\circledast\:1\:horse\:power=746\:W$

Answer 2

Given :

A pump raises water by spending 5×10⁵ J of energy in 10 seconds.

To Find :

Power of the pump.

Solution :

❖ Power is defined as the rate of work done per unit time.

Mathematically, Power = Work / Time

It is a scalar quantity having only magnitude.

SI unit : W (watt)

Dimension formula : [M¹L²T‾³]

♦ We know that work done is always equal to the change in energy.

∴ Work done = 5 × 10⁵ J

By substituting the given values;

$\sf:\implies\:Power=\dfrac{Work}{Time}$

$\sf:\implies\:Power=\dfrac{5\times10^5}{10}$

$\sf:\implies\: Power=5\times10^4$

$:\implies\:\underline{\boxed{\bf{\purple{Power=50\:kW}}}}$

Knowledge BoosteR :

$\sf\circledast\:1\:J=10^7\:erg$

$\sf\circledast\:1\:eV=1.6\times10^{-19}\:J$

$\sf\circledast\:1\:MeV=10^6\:eV$

$\sf\circledast\:1\:amu=931\:MeV$

$\sf\circledast\:1\:kilowatt=10^3\:W$

$\sf\circledast\:1\:horse\:power=746\:W$