2. A quadratic polynomial, whose zeroes are 3 and 4, is
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Answered by
0
Answer:
Quadratic equations = [k( x^2- ( sum of the zeroes) x+( product of the zeroes))]
Step-by-step explanation:
sum of the zeroes = 3
product of tge zeroes =4
[k( x^2-3x+4)]
Your quadratic equation is x^2 - 3x + 4.
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Answered by
0
Answer:
a+B=-3—-b/a
aB=4—c/a
therefore required quadratic polynmial
=x²-(a+B)x+aB
=x²-(-3)x+4
=x²+3x+4
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