Question

2. A quadratic polynomial, whose zeroes are 3 and 4. is (A) r-x+ 12 (B) x+8+12 r (C) (D) 2r + 21-24 2 2 r --- lo​

Answer 1

Answer:

A Quadratic polynomial, whose zeroes are 3 and 4 = (x² - 7x + 12)

Step-by-step explanation:

We can solve this problem in two ways,

Method 1

We have,

Zeroes = 3 and 4

Then,

x = 3 and x = 4

So, factors will be,

(x - 3) and (x - 4)

Then,

p(x) = (x - 3)(x - 4)

p(x) = x² - 4x - 3x + 12

p(x) = x² - 7x + 12

Hence,

A Quadratic polynomial, whose zeroes are 3 and 4 = (x² - 7x + 12)

Method 2

Zeroes = 3 and 4

We know that,

If a polynomial has zeroes a and b,

Then,

The Quadratic equation will be,

p(x) = x² - (a + b)x + (ab)

Here,

Let a = 3

b = 4

So,

p(x) = x² - (3 + 4)x + (3 × 4)

p(x) = x² - 7x + 12

Hence,

A Quadratic polynomial, whose zeroes are 3 and 4 = (x² - 7x + 12)

Hope it helped you and believing you understood it...All the best