2. A rectangle has a perimeter measuring 64 cm. The length is 4 cm
more than 3 times the breadth. Find the dimensions of the
rectangle.
Answers
ANSWER :
Dimensions are 25 cm and 7 cm.
EXPLANATION :
GIVEN :-
- Perimeter of rectangle is 64 cm.
- The length is 4cm more than 3 times the breadth.
TO FIND :
- Dimensions of the rectangle.
SOLUTION :
Let the breadth of the rectangle be x cm.
Length is 4 cm more than 3 times the breadth.
Length = (3x + 4) cm
We know,
Perimeter = 2(3x+4+x) cm
→ Perimeter = 2(4x+4) cm
→ Perimeter = 8(x+1) cm
★ According to the question,
Breadth = 7 cm.
Length = (3 × 7 + 4 ) cm
→ Length = 25 cm
Therefore ,dimensions are 25 cm and 7 cm.
_____________________
★VERIFICATION :
Length of rectangle = 25 cm.
Breadth of rectangle = 7 cm.
Perimeter of rectangle=2(25+7) cm
→ Perimeter of rectangle= 64 cm.
Hence verified___!!
______________________
Given :
- Perimeter of the rectangle = 64 cm.
- The length is 4 cm more than 3 times the breadth.
To find :
- The dimensions of the rectangle =?
Step-by-step explanation:
Perimeter of the rectangle = 64 cm [Given]
Let, The Breadth of the rectangle be x.
Then, The length is 4 cm more than 3 times the breadth be 3x + 4.
We know that,
Perimeter of the rectangle = 2 ( Length + Breadth)
Substituting the values in the above formula, we get,
➮ 64 = 2 ( 3x + 4 + x)
➮ 64 = 2 ( 4x + 4 )
➮ 64 = 8x + 8
Or, 8x + 8 = 64
➮ 8x = 64 - 8
➮ 8x = 56
➮ x = 56/8
➮ x = 7.
Thus, The Breadth of the rectangle x = 7 cm.
Now,
The length of the rectangle, 3x + 4
So, 3x + 4
= 3 × 7 + 4 [x = 7]
= 21 + 4
= 25
Now clearly,
Lenght of the rectangle = 25 cm
Breadth of the rectangle = 7 cm.
Verification :
We know that,
The sum of length, breadth and twice of the length, breadth = Perimeter of the rectangle
So,
2(Lenght + Breadth) = 64
Now, After Substituting the values, we get,
➮ 2 ( 25 + 7) = 64
➮ 2 × 32 = 64
➮ 64 = 64
L. H. S = R. H. S
Hence, it is verified.