Question

2. A rectangle has length 50 cm and breadth 45 cm. A square has its side 48 cm. Which has more
area and by how much?​

Answer 1

Answer:54cm2 more

2304-2250=54

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Given:-

A rectangle has length 50 cm and breadth 45 cm. A square has its side 48 cm.

To find:-

Which has more area and by how much?

Solution:-

Given that:

Length of a rectangle =(l)=50 cm

Breadth of a rectangle=(b)=45cm

We know that

Area of a rectangle = lb sq.units

Area of the given rectangle =

= 50×45 sq.cm

=> 2250 sq.cm

Area of the given rectangle = 2250 sq.cm----(1)

Side of the square = 48 cm

We know that

Area of a square = side×side sq.units

= 48×48 sq.cm

=2304 sq.cm

Area of the given square = 2304 sq.cm -----(2)

From (1) &(2)

Area of a square > Area of a rectangle

Area of a square is greater than area of the rectangle

=> 2304-2250

=> 54 sq.cm

Area of a square is 54 sq.cm more than area of the rectangle

Answer:-

Area of a square is greater than area of the rectangle

Area of a square is 54 sq.cm more than area of the rectangle

Used formulae:-

• Area of a rectangle = lb sq.units

• Area of a square = side×side sq.units

• l = length

• b=breadth