Question

2. A rectangular metal slab has dimensions
15 cm * 10 cm x 5 cm. A cube of side edge
5 cm is cut off from it. Find the volume and
surface area of the remaining slab.​

Answer 1

Answer:

The weight of the metal block of dimension 5cm×4cm×3cm is 1kg.

Its volume=length×breadth×height=5×4×3cm

3

=60cm

3

Again the dimension of the other block which is of same metal is 15cm×8cm×3cm.

Its volume=length×breadth×height=15×8×3cm

3

=360cm

3

∴ The weight of the required block=360cm

3

=6×60cm

3

because weight of 60cm

3

of the metal is 1kg.

=6×1kg

=6kg.