2. A rectangular metal slab has dimensions
15 cm * 10 cm x 5 cm. A cube of side edge
5 cm is cut off from it. Find the volume and
surface area of the remaining slab.
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Answer:
The weight of the metal block of dimension 5cm×4cm×3cm is 1kg.
Its volume=length×breadth×height=5×4×3cm
3
=60cm
3
Again the dimension of the other block which is of same metal is 15cm×8cm×3cm.
Its volume=length×breadth×height=15×8×3cm
3
=360cm
3
∴ The weight of the required block=360cm
3
=6×60cm
3
because weight of 60cm
3
of the metal is 1kg.
=6×1kg
=6kg.
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