Question

2. A rectangular tank measuring 5 m × 4.5 m × 2.1 m is dug in the centre of the field measuring 13.5 m × 12.5 m. The earth dug out is spread evenly over the remaining portion of the field. How much is the level of the field raised?

Answer 1

Step-by-step explanation:

Area of field=13:5×2:5=33:75

Upper area of tank=5×4:5=22:5

Area of field on which soil is spread=33:75_22:5

=11:25m Volume of tank=5×4:5×2:1=47:25m^3

Raised in level=volume of tank/area of field on which

soil spread=47:25/11:25=4:2

So,raised level=4:2m

Answer 2

Step-by-step explanation:

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