Question

2. A second’s pendulum is set up on the surface of the moon , where the acceleration due to gravity is 1/6 th of that of the earth . how is the time period of the pendulum affected ? Give reason to support your answer

Answer 1

Answer:

On surface of moon, acceleration due to gravity is g/6. Time period of seconds pendulum on earth is 2 seconds.

On Earth, 2=2π

g

l

On moon,T

moon

=2π

6

g

l

Dividing the above two equations, we get, T

moon

=2

6

s