2. A shepherd has 200 sheep with him. Find the number of sheeps with him after
3 years if the increase in number of sheeps is 8% every year.
Answers
The number of sheep after 3 years is 251.
Step-by-step explanation:
The exponential increase function is given by
y = a (1 + r)^{t}y=a(1+r)
t
Where a is the initial value, r is the rate of interest in the decimal form and t is the time.
As given
A shepherd has 200 sheep with him.
if the increase in number of sheeps is 8% every year.
a = 200
8% is written in the decimal form.
= \frac{8}{100}=
100
8
= 0.08
t = 3 years
Put all the value in the exponential increase function.
y = 200(1 +0.08)^{3}y=200(1+0.08)
3
y = 200(1.08)^{3}y=200(1.08)
3
y = 200\times 1.2597y=200×1.2597
y = 251.94
y = 251 (Approx)
Therefore the number of sheep after 3 years is 251.
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Answer:
8% every year. therefore increase in 3 years =24%(3×8)
24%of 200=24/100×200=48.
200+48=248 sheep.
therefore,the shepherd will have 248 sheep with him after 3 yearsthe above one is wrong u may calculate bcuz sheep kabhi approximate nahi hoti. kya tumne kabhi aadhi sheep dekhi hai.
so mark as BRAINLIEST