Question

2 (a) Show that for a projectile the angle between the velocity and the x-axis as a function of time is given by -

$t = \tan { }^{ - 1} (v - gt )\div vox$
​

Answer 1

Answer:

Show that, (a) for a projectile the angle between the velocity and the x-axis as a function of time is given by θ(t)=tan−1(voxvoy−gt)(b) Shows that the projection angle θo for a projectile launched from the origin is given by θo=tan−1(R4hm)where the symbols have their usual meaning.

Answer 2

Answer: Show that for a projectile, the angle between velocity and the X-axis as a function of time is given by. θ(t)=tan−1v0xv0y−gt.

Explanation: