Question

2. A soap bubble of radius 10 cm is blown. Surface
tension of soap solution is 30 dyne/cm. Calculate
the work done in blowing the bubble.​

Answer 1

Answer:

here tension is force × length

then work done is same as the tension

answer is 30×1^5 N/m

=3×10^6N/m

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Answer 2

Explanation:

Work Done = (Surface Tension) x (increase in surface area)

Total Work done=2×4π(10010)2×1003

=75.39×10−4J.

We have to do a work of 75.39×10−4J to blow a soap bubble.