Question

2.
A solid has a bcc structure. If the distance of
closest approach between the two atoms is
1.738. The edge length of the cell is:
a) 200 pm
b)V3/ V2 PM
c) 142.2 pm
d) V2 pm

V=square root​

Answer 1

Answer:

The correct option is A .

Explanation:

Distance of closest approach = √3/2a {for BCC }

a = edge length of cell

Given = √3/2a = 173 pm

a = 2×173 /√3 = 200 pm

hope this helps you