Question

2. A speeding car changes its velocity from 108 km/h to 36 km/h in 4 s. Calculatown in
deceleration in (i) ms 2 (ii) kmh ?
[(i) 5 m/s^2 (ii) 64800 km/hr^
2]

Answer 1

Answer:

Explanation:Assuming you are asking constant deceleration.

(I) u = 108x5/18 m/s = 30 m/s

v = 36x5/18 m/s = 10m/s

t = 4 sec

a = (v-u)/t = (10 - 30) /4 = -5m/s²

*Deceleration = 5 m/s²*

(II) t = 4/3600 hr

a = (v-u)/t

(36-108)/(4/3600) = -64800km/hr²

*Deceleration = 64800 km/hr²*

Hope It Helps...

Answer 2

Answer:

5m/s^2

Explanation:

or 64800 km/h^2