Question

2. A stone is dropped from the edge of a roof. Find the distance travelled by the stone in 2 s after its release. Take,g=9.8m/s
[Ans. 19-6 ms
g = 9.8 m s-2
3​

Answer 1

(initial velocity) . we need to find V(final velocity).

and time given is 2 sec.

here g = 9.8 .

so v=u+gt

V=0+9.8×2

V=19.6

To find the distance we can use

2gs=v²-u²

2×9.8×s=(19.6)²-(0)²

19.6×s=384.16

s=384.16÷19.6

s=19.6m

Answer 2

Answer:

I think this will help you

Explanation:

a=g=9.8 m/s

u=0m/s

t=2secound

v=?

v=u+at