Question

2 A stone IS thrown vertically upward With an mitral speed of 19 5 m/s If the magmtude of Its acceleration IS 9 80 m/s2 , It Will rise to a maximum height of
1 4 9 m
2 98m
3 19 4 m
4 38 8 m
5 53 8 m (3

Answer 1

Explanation:

Vi= 19.4 approximately =19.5

Vf= 0m/s

a= - 9.8 m/s^2

d=?

Since we have those informations. Use

Vf^2 = 2ad + vi^2

When it reaches the maximum height, it's final velocity is 0 m/s

(0m/s)^2 = 2(-9.8m/s^2) d + (19.5m/s)^2 - 380.25m^2 /s^2 = (-19.6m/s^2) d

d= 19.4m

Here is your answer

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