Question

2. A stone of mass 4 kg is attached to a string of 10 m
length and is whirled in a horizontal circle. The
string can withstand a maximum tension of 160 N.
Calculate the maximum velocity of revolution that
can be given to the stone without breaking the
string
(Ans. 20 ms-1)​

Answer 1

Answer:

20m/s

Explanation:

For circular motion,

Maximum tenstion = Centripetal force

∴T = mv²

r

Given, T = 160 N, m = 4 kg, r = 10 m

160 = 4 × v²

10

160 × 10 = 4 × v²

v² = 1600

4

v² = 400

v = √400

v = 20m/s

Answer 2

Answer:

A stone of mass 4 kg is attached to a string of 10 m

length and is whirled in a horizontal circle. The

string can withstand a maximum tension of 160 N.

Calculate the maximum velocity of revolution that

can be given to the stone without breaking the

string

Answer: 20m/s