Question

2. A stone of mass 800g is Submerged
in water taken in a beaker. If the
mass of displaced water is 2009,
calculate the weight of stone in
coater (value of g = 10mise)​

Answer 1

Answer:

First, calculate the loss in mass = 100 g - 80 g = 20 g h2o displaced

The density of water = 1 g / mL

So, the object displaced 20 mL of water, which equals the volume of the object.

With that, we can calculate the relative density when kept in water, which equals -> mass / volume

The object’s relative density = 80 g / 20 mL

Then the relative density = 4 g / mL

If an object has a relative density greater than the liquid you’re putting it in, then it will sink. In this case, the relative density of the object is 4g / mL, which is greater than the 1 g / mL for water. So, the object would sink.