Question

2 A straight line has equation y = -x + 6. Which of the following lines is/are
parallel to it?
a 2(y + x) = -5 b -3x – 3y + 7 = 0
1
c2y = -x + 12
x
d y + x =
10​

Answer 1

Answer:

2y +2x=-5

Step-by-step explanation:

as parallel lines are a/A1=b/b1=c/c1

Answer 2

Answer:

c) $2y = -2x + 12$

Step-by-step explanation:

Concept: If two line $a_{1}x + b_{1}x + c_{1}x = 0$ and $a_{2}x + b_{2}x + c_{2}x = 0$ are parallel to each other then,   $\frac{a_{1} }{a_{2}} = \frac{b_{1} }{b_{2}} = \frac{c_{1} }{c_{2}}$

Solution:

the line given $y = -x + 6$  ⇒  $x + y - 6 = 0$

for the first one, $\frac{1}{2} = \frac{1}{2} \neq \frac{-6}{-5}$  are not equal so they are not parallel

now the second one, $\frac{1}{-3} = \frac{1}{-3} \neq \frac{-6}{-7}$ are not equal so they are not parallel

for the third one, $\frac{1}{2} = \frac{1}{2} = \frac{-6}{12}$ are equal therefore they are parallel

#SPJ3