Question

2) A submarine was situated 200.m below sea level. If it descends 180m, what
is its
new position

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Answer 1

Answer:

$let \: the \: initial \: position \: of \: the \: submarine \: be \: - 240m. \\ \\ distance \: descended = 160m. \\ \\ new \: position = - 240 - 160(since \: the \: submarine \: descended) \\ \\ = - 400m. \\ \\ distance \: ascended = 390m. \\ \\ final \: position = - 400 + 390 = - 10m. \\ \\ multiplying \: with \: ( - ) \: sign. \: we \: get \: 10m. \\ \\ therefore \: the \: new \: position \: of \: the \: submarine \: is \: 10m \: below \: the \: sea \: level.$

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Answer 2

Answer:

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