Question

2. A sum of the present ages of a mother and daughter is 63. Three years back if the age of the mother was double that of the daughter then the present age of the daughter is:​

Answer 1

Answer:

$let \: moters \: age \: be \: x \: and \: daughtrs \: ag \: be \: y \\ x + y = 63 \\ \\ x - 3 = 2(y - 3) \\ x - 3 = 2y - 3 \\ x - 2y = 0 \\ subtracting \: both \: the \: equations \\ x + y - x + 2y = 63 \\ 3y = 63 \\ y = 21$