Physics, asked by nileshpatel11, 11 months ago

(2)
A thermally insulated pot has 150 g ice at
temperature 0°C. How much steam of 100°C has
to be mixed to it, so that water of temperature
50°C will be obtained?
ON
Ans. Given:
Steam
Ice
m,
150g
(m)
(c)
1 cal/g°C
100°C
50°C
540 cal/
g
1 cal/g°C
0°C
50°C
8 0 cal/g
To find: m



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Answered by Ruchadeshmukh1
2

Hope its too helpful

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Answered by Arpita2000chihnara
0

Answer:

hey bro here is your answer

Explanation:

33g please mark as brainlist

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