Question

2.
A total charge of 360 coulombs is passed through 800 resistor in 30 seconds. Determine the
amount of heat generated.
(3marks)​

Answer 1

Answer:

irst let’s know the general law:

I=Qt

Where:

I is the current measured in amperes (A).

Q is the charge measured in coulombs (C).

t is the time measured in seconds (s).

Now you just need to substitute nothing more:

I=Qt

Then:

Q=I∗t=10∗(1∗60)=10∗60=600 C

So your question answer simply:  600 coulombs

Explanation: