Question

2. A tower stands vertically on the ground from a point on the ground which is 100 m away from
the foot of the tower, the angle of elevation of the top of the tower is found to have measure 50
Find the height of the tower.​

Answer 1

Answer:30m away / 45  

∘

 inclination.

Let the height of tower be h m

so AB=hm

Distance of the point from

foot of tower = 30m  

CB=30m

Angle of elevation =45  

∘

 

∠ACB=45  

∘

 

Since tower is vertical to ground

∠ABC=90  

∘

 

Now tanC=  

sideadjacenttoangleC

sideopptoangleC

​  

 

tanC=  

CB

AB

​  

 

tan45=  

CB

AB

​  

 

1=  

30

H

​  

 

H=30

Hence height of tower = 30m

Answer = option C=30m