Question

2. A train accelerates uniformly from 36 km/h to 72 km/h in 20 s. Find the distance travelled by it.​

Answer 1

Answer:a=v - u

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t

= 72 * 5/18 - 36 * 5/18

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20

= 10/20

= 1/2 m/square

2aS = v sq. - u sq.

S = 400 - 100 = 300m

distance = 300 m

Step-by-step explanation:

Answer 2

Answer:

600m

Step-by-step explanation:

u=36km/h=10m/s

v=72km/h=20m/s

t=20s

a=20-10/20=.5m/s^2

s=ut+1/2at^2

=10×20+1/2×5/10×400

= 200+100

= 300m