Physics, asked by manojjjreddyyy, 9 months ago

2. A train is travelling at a speed
of 90 km h-!. Brakes are applied
so as to produce a uniform
acceleration of - 0.5 m s2. Find
how far the train will go before it
is brought to rest.​

Answers

Answered by khanrehana20525
3

Answer:

plz mark as brainlist answers

Answered by chaviLOVER
2

Answer:

Speed of train , u = 90 km/h = 90 × 5/18 = 25 m/s

acceleration , a = -0.5 m/s²

Use formula,

v = u + at

Finally train will be rest so, final velocity, v = 0

0 = 25 - 0.5t

25 = 0.5t ⇒t = 50 sec

Again, use formula,

S = ut + 1/2at²

Where S is distance travelled before stop

S = 25 × 50 - 1/2 × 0.5 × 50²

= 1250 - 1/2 × 0.5 × 2500

= 1250 - 625

= 625 m

Hence, distance travelled = 625m and time taken = 50 sec

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