Question

2. A train is travelling at a speed of
90 kmh Brakes are applied so
as to produce a uniform
acceleration of - 0.5 ms. Find
how far the train will go before it
is brought to rest.
of al
the
trac
run
AB,​

Answer 1

Answer:

its answer yaa yaa blaaa

Explanation:

sorry mate i also not know i amin class8

Answer 2

Distance travelled (s)=625 m

---------------------------

Given:

• Initial speed (u) = 90 km/h = 25 m/s

• Final speed (v) = 0 m/s (Rest)

• Accelration (a) = -0.5 m/s²

Explanation:

$\begin{gathered}\rm From \: 3^{rd} \: equation \: of \: motion \: we \: have: \\ \boxed{ \bf{ {v}^{2} = {u}^{2} + 2as}}\end{gathered}$

s → Distance travelled

By substituting values in the equation we get:

$\begin{gathered}\rm \implies {0}^{2} = {25}^{2} + 2( - 0.5)s \\ \\ \rm \implies 0 = 625 - 1s \\ \\ \rm \implies s = 625 \: m\end{gathered}$

$⟹0 </p><p>2</p><p> =25 </p><p>2</p><p> +2(−0.5)s \\ </p><p>⟹0=625−1s \\ </p><p>⟹s=625m</p><p>$

$hope \: its \: help \: u$