Question

2. A tree is broken at a height of 4 cm from the ground. Its top touches the ground at a distance of 3cm from the base of the tree. Find the original height of the tree
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Answer 1

♫ Given :

A tree is broken at a height of 4 cm from the ground. Its top touches the ground at a distance of 3cm from the base of the tree

♫ To Find :

Original height of the tree

♫ Solution :

Observe attachment for entire scenario .

The whole scenario resembles right angled triangle where ,

• Base (B) = 3 cm
• Height (h) = 4 cm
• Hypotenuse (H) = H cm

★ Apply Pythagoras theorem ,

➠ H² = B² + h²

➠ H² = 3² + 4²

➠ H² = 9 + 16

➠ H² = 25

➠ H = 5 cm  $\pink{\bigstar}$

Total height of the tree = height + Hypotenuse

                                       = h + H

                                       = 4 + 5

                                       = 9 cm $\green{\bigstar}$

★══════════════════════★

Answer 2

Solution

Base (B) = 3 cm

Height (h) = 4 cm

Hypotenuse (H) = H cm

Apply Pythagoras theorem ,

➠ H² = B² + h²

➠ H² = 3² + 4²

➠ H² = 9 + 16

➠ H² = 25

➠ H = 5 cm

Total height of the tree = height + Hypotenuse

= h + H

= 4 + 5

= 9 cm