Question

2. A tree is broken at a height of 5m from the ground and its top touches the ground at a
distance of 12m from the base of the tree. Find the original height of the tree.​

Answer 1

Answer:

the original height is 13m

Step-by-step explanation:

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Answer 2

Given :-

Height = 5m

Distance from the base of the tree = 12m

To Find :-

The Original Height of the Tree.

Formula Used :-

$\sf{{(Hypotenuse)}^{2} = {(Base)}^{2} + {(Perpendicular)}^{2}}$

Solution :-

In ∆ ABC : -

(AC)² = (BC)² + (AB)²

(AC)² = (12)² + (5)²

(AC)² = 144 + 25

(AC)² = 169

$\sf{{(AC)}^{\cancel{2}}={(13)}^{\cancel{2}}}$

AC = 13m

So :-

Original Height of tree = 13 + 5

18 m

Therefore , The Original Height of the Tree is 18 m ..