2. A triangle and a parallelogram are constructed on the same base such that their areas are equal. If the altitude
of the parallelogram is 100 m, then find the altitude of the triangle.
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Answer:
200
Step-by-step explanation:
We need to find the altitude of the triangle.
let the triangle and parallelogram have common base b,
let the altitude of the triangle is h1 and of parallelogram is h2 (which is equal to 100 m), then
area of triangle =1/2 × b×h1
area of parallelogram =b×h2
As per given,
1/2×b×h1=b×h2
1/2×b×h1=b×100
h1=200
Hence altitude of triangle =200
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