Question

2.A trolley, while going down aninclined plane, has anacceleration of 2 cm s-2. What willbe its
velocity 3 s after the start?

Answer 1

Answer:

The "velocity of the trolley" at 3 s is 0.06 m/s .

Given data:

Acceleration, a = 2 cm/s^2 = 0.02 m/s^2

To find:

Velocity after 3 s = ?

Solution:

The trolley is on the inclined plane,

Thereby, the first equation of motion is to be applied to calculate velocity after 3 sec.

Therefore, we have,

t = 3 sec

u = 0

a=2 \ \mathrm{cm} / \mathrm{s}^{2}=0.02 \ \mathrm{m} / \mathrm{s}^{2}a=2 cm/s

2

=0.02 m/s

2

v=u+a tv=u+at

v=0+(0.02 \times 3)v=0+(0.02×3)

\Rightarrow v=0.06 \ m / s⇒v=0.06 m/s

Explanation:

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