Question

2. A two-digit number has the same digit in its ones and tens places. It is also divisible by both
7 and 11. Find the number.​

Answer 1

Answer:

77

Step-by-step explanation:

77 is divisible by both 7 and 11

Answer 2

Answer:

77

Step-by-step explanation:

Let the digits are x and x

then Number N= 10x+x=11x

N=11*x

Thus all such nubers whose unit digit and ten's digit are same

like 11,22,33,..............................99

Now we want that N is divisible by 7 also

so N=7*q ( q is an integer)

7q=11x

q=11x/7

Since x is an intger this is possible only if x is multiple of 7

x=7m ( m is an integer>0)

if m=1 then x=7

Them N=11*7=77

If m=2 then x=14

Then N=11*14=154 this is not a 2 digit number

Thus only such no is 77