2. A wedge of mass "2m' and a cube of mass m are shown in figure Between cube
friction. The minimum coefficient of friction between wedge and ground so that wedondo
wn in figure. Between cube and we
nd so that wedge does not
2m
5
= 45
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Given:
A wedge of mass 2m' and a cube of mass m are shown in the figure. Between cube and wedge, there is friction.
To find:
The minimum coefficient of friction between wedge and ground so that wedge does not move is
Solution:
Now let the coefficient of friction is μ
Let for cube the horizontal force be f
f = mgcosθsinθ
f = mgcos(45)sin(45)
f = mg/2
Let for wedge the reaction from ground be N
N = 2mg+mg(cos45)²
= 2mg+mg/2
N = 5mg/2.
f = μN
Where μ is the coefficient of friction
μ N = mg/2
μ(5mg/2)= mg/2
μ = 1/5
Therefore, the minimum coefficient of friction between wedge and ground so that wedge does not move is 1/5
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