Question

2). A wire is 1.0 m long, 0.2 mm in diameter and has a resistance of 10 Q. Calculate the te
material ?
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Answer 1

Solution:

d = 0.2mm = 0.2×10^-3m = 2×10^-4m

=> r = 1×10^-4 m

L = 1m  

A = πr²

= 3.14×(1×10^-4)²  

= 3.14×10^(-8) m²

R = 10 ohms

resistivity = R×A/L

= 10×3.14×10^(-8)/1

= 3.14×10^(-7) ohm m