Question

2. A wire is framed in shape of rectangle with length 15cm and breadth 10 cm.. it is changed in the shape of square. Find area of square.​

Answer 1

Answer:

Let a be the side of a square, l be the length and b be the breadth of rectangle.

As length of wire is constant, perimeter of both shapes would be same,

⇒4a=2(l+b)

⇒40=2(12+b)

⇒b=18 cm

Area of square=a

2

=10

2

=100cm

2

Area of rectangle=lb=12×18=216cm

2

⇒ Area of rectangle is greater by 116cm

Answer 2

Answer:

perimeter of rectangle=2(l+b)

2(25)

50cm

according to question,

perimeter of rectangle=perimeterof square

50=4(side)

side=50/4

side=12.5

area of square=(side)²

=(12.5)²

=156.25cm²

Step-by-step explanation:

thanks,