Math, asked by hermonie83, 9 months ago

2. (a) Write a pair of negative integers whose difference gives 8.
(b) Write a negative integer and a positive integer whose sum is -5.
(c) Write a negative integer and a positive integer whose difference is -3. PLZZ answer alphabet wise​

Answers

Answered by rekhabisht15385
0

Answer:

2.a -3-(-11)=8

Step-by-step explanation:

dyigggxgxuochpvj

Answered by anjalisingh2006
0

Answer:

Step-by-step explanation:

-10 and -2

(-1,-9) and (-3,-11) are two pairs whose difference is 8.

(-1,-9) and (-3,-11) are two pairs whose difference is 8.We can write infinitely many pairs .

Step-by-step explanation:

Negative Integers = { .......,-5,-4,-3,-2,-1}

Let -1, -9 are two negative integers.

i )Difference of two numbers = -1-(-9)

= -1 + 9

= 8

ii) Let -3, -11 are two negative integers.

Difference of these two numbers = -3-(-11)

= -3+11

= 8

Therefore,

(-1,-9) and (-3,-11) are two pairs whose difference is 8

b) 15 + ( - 20 )

15 - 20

- 5

c) -1 and 2

Step-by-step explanation:

2-(-1)=3

Similar questions