Math, asked by salmarida22921, 9 months ago

2(a²+¹/a²)-(a-¹/a)-7​

Answers

Answered by sanghmitrasingh20299
1

Answer:

2[(a^2+1)/a^2] - [(a-1)/a] -7 = 0

(2a^2+2-a^2+a) / a^2 = 7

a^2 + a + 2 = 7a^2

a+2 = 6a^2  

6a^2 - a - 2 = 0

6a^2 + 3a - 4a - 2 = 0

0= 3a(2a+1) - 2(2a+1)

0= (3a-2) (2a+1)

0= 3a-2 \ 0= 2a+1

2= 3a \ 2a= -1

a=2/3 \ a = -1/2

Step-by-step explanation:

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