2(a²+¹/a²)-(a-¹/a)-7
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Answer:
2[(a^2+1)/a^2] - [(a-1)/a] -7 = 0
(2a^2+2-a^2+a) / a^2 = 7
a^2 + a + 2 = 7a^2
a+2 = 6a^2
6a^2 - a - 2 = 0
6a^2 + 3a - 4a - 2 = 0
0= 3a(2a+1) - 2(2a+1)
0= (3a-2) (2a+1)
0= 3a-2 \ 0= 2a+1
2= 3a \ 2a= -1
a=2/3 \ a = -1/2
Step-by-step explanation:
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