Math, asked by kankana04, 1 year ago

2(a2+1/a2)-(a-1/a)-7

Answers

Answered by devgandhi1113
13

Answer: a = 2/3 ; a = -1/2


Step-by-step explanation:


2[(a^2+1)/a^2] - [(a-1)/a] -7 = 0


(2a^2+2-a^2+a) / a^2 = 7


a^2 + a + 2 = 7a^2


a+2 = 6a^2


6a^2 - a - 2 = 0


6a^2 + 3a - 4a - 2 = 0


0= 3a(2a+1) - 2(2a+1)


0= (3a-2) (2a+1)


0= 3a-2 \ 0= 2a+1

2= 3a \ 2a= -1

a=2/3 \ a = -1/2

Answered by devilqueen012
4

Answer:

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