Question

2(a²+b²)=(a+b)²+(a-b)²

Answer 1

RHS
(a+b)²+(a-b)²
apply identities
a²+b²+2ab+a²+b²-2ab
2a²+2b²
taking 2 as common
2(a²+b²)=LHS
hence proved

Answer 2

we have to prove that 2(a2+b2) = (a+b)2+(a-b)2
Note. where 2 written it square

Now ,
simplifying RHS then,
identity (a+b)2 = a2+ b2 + 2ab
(a-b)2 = a2 + b2 -2ab
then,
a2 +b2+2ab + a2 + b2 -2ab
by cancelling 2ab - 2ab
then,
taking 2 as common ,

2 ( a2 + b2 )
hence proved ,
2 (a2 + b2 ) = 2 ( a2 + b2 )

Hoped it helped u ....... ✌✌✌✍