Question

2. A5000 kg engine pullsa train of 4 wagons, each of 1500 kg, along a horizontal track. If the engine exerts
aforce of 24,000 Nand the trackoffers a frictional force of 2000 N, then calculate:
a thenetaccelerating force
b. the acceleration of the train
c the force of wagon 2 onwagon3​

Answer 1

Answer:

Mass of the engine = 5000 kg 

Mass of each wagon = 2000 kg, 

Np. of wagons = 5 

Total mass of train = 8000+2000×5= 18000 kg 

Force, F = 40000 N 

Track resistance , R = 5000 N 

Total accelerating force = F −R =40000−5000=35000 N 

Let acceleration = x m/s² 

Acceleration , = Accelerating force / mass 

x=35000/18000= 35/18=1.94 m/s² 

Frictional resistance of 4 wagons = 5000×(2000×4)/18000 =2222 .22 N 

Accelerating force on 4 wagons =2000×4×1.944 =15552 N 

Hence total force exertred by wagon on wagon 2= Accelerating force +Frictional resistance 

=2222 .22 +15552=17774.22 N 

Total force required to produce acc

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Explanation:

Answer 2

Answer:

net accelerating force=22000 N

acceleration of train =22000/11000

=2 m/s^2

force of wagon 2 on wagon 3=3000×2

=6000 N