Question

2(ab + cd) - a2 - b2 + 2 + d2​

Answer 1

I THINK HERE YOUR QUESTION IS WRONG

( THERE WILL BE C^2 IN PLACE OF 2 )

=》 2(ab + cd) - a^2 - b^2 + c2 + d^2

=》 2ab + 2cd - a^2 - b^2 + c^2 + d^2

=》c^2 + d^2 + 2cd - a^2 - b^2 + 2ab

=》( c^2 + d^2 + 2cd ) - ( a^2 + b^2 - 2ab )

=》 ( c + d )^2 - ( a + b )^2

{ Here it is in form of whole square }

=》 ( c + d + a - b ) ( c + d - a +b )