Question

2) ∆ABC is right angled at A and AD is the altitude to side BC. If AB=8 cm and
AC= 15cm ,then BC=?
1) 12 cm
2) 7 cm
3) 17 cm
4) 5 cm
please answer correctly guys !!​

Answer 1

Step-by-step explanation:

using Pythagoras theorem

(AB)² + (AC)²= (BC)²

(8)²+ (15)²=BC²

64+ 225= BC²

✓289= BC

17cm = BC

hope it helps...

Answer 2

Hypotenuse (BC) = 17 cm

Option (3) is correct.

Given:

• In ∆ABC is right angled at A and AD is the altitude to side BC.
• If AB=8 cm and AC= 15cm.

To find:

• Find the value of BC.
• 1) 12 cm
• 2) 7 cm
• 3) 17 cm
• 4) 5 cm

Solution:

Concept/Formula to be used:

• Apply Pythagoras theorem.
• Pythagoras theorem: In right triangle Hypotenuse²= Base²+ Perpendicular²

Step 1:

Write the given dimensions.

As it is clear from the attachment.

AB(Perpendicular)= 8 cm

AC(Base)=15 cm

BC(Hypotenuse)=?

Step 2:

Apply values in the theorem.

${BC}^{2} = ( {15)}^{2} + ( {8)}^{2}$

or

${BC}^{2} = 225 + 64$

or

${BC}^{2} = 289$

or

${BC} = \sqrt{289}$

or

$\bf {BC} = 17 \: cm$

Thus,

Hypotenuse (BC) = 17 cm.

Option (3) is correct.

Learn more:

1) AB=AC and ∠A is right angle in ΔABC. If BC = √2 a, then find the area of the triangle. (a ∈ R, a > 0)

https://brainly.in/question/5033701

2) If length of a diagonal of rhombus is 30 cm ahd its 240sq cm find it perimeter

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