Question

2. ABC isosceles triangle with AB = AC and D is a point on BC such that
AD perpendicular to BC (Fig. 7.132. To prove that ZBAD - ACAD, a student proceeded as

Answer 1

Step-by-step explanation:

In an isosceles triangle ABC with AB = AC, D and E are points on BC such that BE = CD. ... So, now all the corresponding sides and angles of triangles ABD and ACE are equal by the C.P.C.T property of congruent triangles.

Answer 2

Answer:

It is defective to use ∠ABD=∠ACD for proving this result.

△ABD and △ACD

AB=AC  (given )

Then ∠ABD=∠ACD ( because AB=AC )

and  ∠ADB=∠ADC=90( because AD⊥BC )

∴△ABD=△ACD

∠BAD=∠CAD

It is defective to use ∠ABD=∠ACD for proving this result