Question

2.
ABCD is a
thombus such that LACB=40%,
then LADB= ? ?​

Answer 1

Step-by-step explanation:

(C) 50º Explanation: According to the question, ABCD is a rhombus ∠ACB = 40° ∵ ∠ACB = 40° ⇒ ∠OCB = 40° ∵ AD ∥ BC ⇒ ∠DAC = ∠BCA = 40° [Alternate interior angles] ⇒ ∠DAO = 40° Since, diagonals of a rhombus are perpendicular to each other We have, ∠AOD = 90° We know that, Sum of all angles of a triangle = 180° ⇒ ∠AOD + ∠ADO + ∠DAO = 180° ⇒ 90° + ∠ADO + 40° = 180° ⇒ 130° + ∠ADO = 180° ⇒ ∠ADO = 180° – 130° ⇒ ∠ADO = 50° ⇒ ∠ADB = 50° Hence, ∠ADB = 50° Therefore, option (C) is the correct answerRead more on Sarthaks.com - https://www.sarthaks.com/871739/abcd-is-a-rhombus-such-that-acb-40-then-adb-is-a-40-b-45-c-50-d-60

Answer 2

Answer:

Given Question: -

ABCD is a

ABCD is athombus such that LACB=40%,

ABCD is athombus such that LACB=40%,then LADB= ? ?

Correction in question

--->ABCD is a rhombus such that ∠ACB=40othen ∠ADB is ___ .

Your answer: -

ABCD is a rhombus such that ∠ACB=40othen ∠ADB is _50°